F(x)=-2x^2-16+5

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Solution for F(x)=-2x^2-16+5 equation: 



(F)=-2F^2-16+5

We move all terms to the left:

(F)-(-2F^2-16+5)=0

We get rid of parentheses

2F^2+F+16-5=0

We add all the numbers together, and all the variables

2F^2+F+11=0

a = 2; b = 1; c = +11;
Δ = b2-4ac
Δ = 12-4·2·11
Δ = -87
Delta is less than zero, so there is no solution for the equation

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